ABC26PH0191 · Solid State Chemistry

Subject: Physical Chemistry · Chapter: Solid State Chemistry · Topic: Solid State Chemistry – General · Exam: CSIR-NET 2011 · Marks: 2 · Difficulty: Easy

\[ \begin{array}{l} 325.6=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{a}{\sqrt{3}} \Rightarrow a=325.6 \times \sqrt{3} \mathrm{d}_{333}=\frac{325.6 \times \sqrt{3}}{\sqrt{3^{2}+3^{2}+3^{2}}}=\frac{325.6 \times \sqrt{3}}{\sqrt{27}}=108.5 \mathrm{pm} \end{array} \]
3. Consider a n-type semiconductor whose $\mathrm{E}, = \mathrm{0}, \mathrm{E}_{\mathrm{C}}=\mathrm{2 . 0eV}$ and $\mathrm{E}_{\mathrm{D}}-\mathrm{1 . 98eV}$. The correct statement among the following is
(a)$\mathrm{E}_{\mathrm{F}}=\mathrm{leV}$ and is independent of T
(b)$\mathrm{E}_{\mathrm{F}}=\mathrm{1 . 99 ~ eV}$ and remains independent of T
(c)$\mathrm{E}_{\mathrm{F}}=\mathrm{1 . 99 ~ eV}$ and increases towards 2.0 eV with increase of T
(d)$\mathrm{E}_{\mathrm{F}}=1.99 \mathrm{eV}$ and decreases with increase of T.
Answer
SELF-PRACTICE — the source book printed no answer.

Nothing is invented here, so this question has no answer on record.

Explanation
No explanation was printed for this question.

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