ABC26PH0198 · Statistical Thermodynamics

Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Thermodynamics – General · Exam: CSIR-NET JUNE 2012 · Marks: 2 · Difficulty: Medium

The correct entropy for 6 identical particles with their occupation number $0,1,2,3$ in four steps is :

(a)$k_{A} \ln 8$

(b)$k_{A}ln 12$

(c)$k_{B}ln 60$

(d)$k_{D} \ln 720$

Answer

Answer (as printed): C

Explanation

$S=K_{B}\ln W$ ......(1). Where $W=$ number of arrangements $=\dfrac{6!}{0!\,1!\,2!\,3!}=60$. From equation (1), $S=K_{B}\ln 60$.

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