ABC26PH0202 · Statistical Thermodynamics

Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Equilibrium · Exam: CSIR-NET JUNE 2014 · Marks: 2 · Difficulty: Medium

The number of configurations in the most probable state, according to Boltzmann formula, is

(a)$e^{\frac{S}{k_{B}}}$

(b)$e^{\frac{-S}{k_{B}}}$

(c)$e^{\frac{-E}{k_{B} T}}$

(d)$e^{\frac{-\Delta G}{k_{B} T}}$

Answer

Answer (as printed): A

Explanation

$S=k_{b}\ln W$ $S/k_{b}=\ln W$ $W=e^{S/k_{B}}$

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