ABC26PH0219 · Surface Chemistry

Subject: Physical Chemistry · Chapter: Surface Chemistry · Topic: Catalysis Surface · Exam: CSIR-NET DEC 2019 · Marks: 2 · Difficulty: Hard

The order of a surface catalyzed unimolecular reaction, at very low and very high pressures of the reactant, would be, respectively

(a)0,0

(b)1,0

(c)0,1

(d)1,1

Answer

Answer (as printed): B

Explanation

$\theta=\dfrac{kP}{1+kP}$. At very low pressure, $kP \ll 1$; $\theta=kP$ (first order). At very high pressure, $kP \gg 1$; $\theta=1$ (zero order).