Question Bank › Physical Chemistry › Electrochemistry › ABC26PH0387Given the standard potential for the following half-cell reaction at 298 K Cu⁺(aq)+e⁻ → Cu(s) E₀=0.52 V… · ABC26PH0387 Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Nernst Cells · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Hard
Given the standard potential for the following half-cell reaction at 298 K \[ \begin{array}{ll} \mathrm{Cu}^{+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Cu(s)} & \mathrm{E}_{0}=0.52\,\mathrm{V} \\ \mathrm{Cu}^{2+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Cu}^{+}(\mathrm{aq}) & \mathrm{E}_{0}=0.16\,\mathrm{V} \end{array} \]
Calculate the $\Delta \mathrm{G}^{0}(\mathrm{kJ})$ for the reaction, $2\mathrm{Cu}^{+}(\mathrm{aq}) \rightarrow \mathrm{Cu}^{+}(\mathrm{s})+\mathrm{Cu}^{2+}$ (a) -34.740
(b) -65.720
(c) -69.480
(d) -131.40
Answer Answer: A ✓ checked by 4AB · confidence high
Explanation 2Cu⁺ → Cu + Cu²⁺: E° = 0.52 − 0.16 = 0.36 V, ΔG° = −1 × 96485 × 0.36 = −34.7 kJ (a).
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