ABC26PH0646 · Chemical Equilibrium

Subject: Physical Chemistry · Chapter: Chemical Equilibrium · Topic: Chemical Equilibrium – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium

For the equilibrium $\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}$, the equilibrium constant, $\mathrm{K}_{\mathrm{P}}$ is expressed as
(a)$3^{ɔ} \mathrm{K}_{\mathrm{p}}=\frac{\cdots_{\mathrm{m}_{2}}}{\mathrm{p}_{\mathrm{N}_{2}}^{2}}$
(b)$3^{5} \mathrm{K}_{\mathrm{p}}=\frac{\mathrm{p}_{\mathrm{N}_{2}} \mathrm{p}_{\mathrm{H}_{2}}^{3}}{\mathrm{p}_{111} \mathrm{s}_{2}}$
(c)$3^{3}\,\mathrm{K_p} = \dfrac{p_{\mathrm{NH_3}}^{2}}{p_{\mathrm{N_2}}^{4}}$
(d)$3^{3/2}\,\mathrm{K_p}^{1/2} = \dfrac{p_{\mathrm{NH_3}}^{2}}{p_{\mathrm{N_2}}^{4}}$
Answer
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Explanation
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