The turnover frequency (TOF) for the catalytic reaction, A(1 mol) [ 5 hours ] Catalyst (0.01 mol) B with 90\% yield of the product is ____ hour -1(Round off to the nearest integer)

ABC26PH0658 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium

The turnover frequency (TOF) for the catalytic reaction,

\[ \mathrm{A}(1 \mathrm{mol}) \xrightarrow[\text { 5 hours }]{\text { Catalyst }(0.01 \mathrm{mol})} \mathrm{B} \]

with 90\% yield of the product is ____ hour ${ }^{-1}$(Round off to the nearest integer)

Answer

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