ABC26PH0674 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Hard

The mechanism of isomerization of cyclobutene (CB) to 1, 3-butadiene (BD) is as follows.
\[ \begin{array}{l} \mathrm{CB + CB \xrightarrow{k_1} CB^{*} + CB} \\ \mathrm{CB^{*} + CB \xrightarrow{k_{-1}} CB + CB} \\ \mathrm{CB^{*} \xrightarrow{k_2} BD} \end{array} \]
(a)Show that the rate law is $\frac{\mathrm{d}[\mathrm{BD}]}{\mathrm{dt}}=\frac{\mathrm{k}_{2} \cdot \mathrm{k}_{1} \cdot[\mathrm{CB}]^{2}}{\mathrm{k}_{-1} \cdot[\mathrm{CB}]+\mathrm{k}_{2}}$
(b)The apparent first-order rate constant, $\mathrm{k_{app}} = \dfrac{\mathrm{k_2 \cdot k_1 \cdot [CB]}}{\mathrm{k_{-1} \cdot [CB] + k_2}}$. At the CB concentration of $1 \times 10^{-5}$ mol ____ ratio $\dfrac{\mathrm{k_2}}{\mathrm{k_{-1}}}$.
Answer
SELF-PRACTICE — the source book printed no answer.

Nothing is invented here, so this question has no answer on record.

Explanation
No explanation was printed for this question.

Open in whiteboard · Browse this chapter in the app