ABC26PH0885 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Arrhenius Activation · Exam: NET JUNE 2012 · Marks: 2 · Difficulty: Medium

For a reaction, the rate constant k at $27^{\circ} \mathrm{C}$ was found to be $\mathrm{k}=5.4 \times 10^{11} \mathrm{e}^{-50}$. The activation energy of the reaction is:
(a)$150 \mathrm{J} \mathrm{mol}^{-1}$
(b)$1415 \mathrm{J} \mathrm{mol}^{-1}$
(c)$115,000 \mathrm{J} \mathrm{mol}^{-1}$
(d)$1125,000 \mathrm{J} \mathrm{mol}^{-1}$
Answer
SELF-PRACTICE — the source book printed no answer.

Nothing is invented here, so this question has no answer on record.

Explanation
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