ABC26PH0915 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Arrhenius Activation · Exam: NET DEC 2014 · Marks: 2 · Difficulty: Hard

A reaction $\mathrm{A}+\mathrm{B}+\mathrm{C} \rightarrow \mathrm{D}$ follows the mechanism
\[ \begin{array}{l} \mathrm{A}+\mathrm{B} \leftrightharpoons \mathrm{AB} \\ \mathrm{AB}+\mathrm{C} \rightarrow \mathrm{D} \end{array} \]
in which first step remains essentially in equilibrium. If $\Delta \mathrm{H}$ is the enthalpy change for the first reaction and $\mathrm{E}_{0}$ is the activation energy for the second reaction, the activation energy of the overall reaction will be given by
(a)$\mathrm{E}_{0}$
(b)$\mathrm{E}_{0}-\Delta \mathrm{H}$
(c)$\mathrm{E}_{0}+\Delta \mathrm{H}$
(d)$\mathrm{E}_{0}+2 \Delta \mathrm{H}$
Answer
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Explanation
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