ABC26PH0929 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Exam: NET DEC 2015 · Marks: 2 · Difficulty: Hard

If the rates of a reaction are $\mathrm{R}_{1}$ and $\mathrm{R}_{2}$ at concentrations $\mathrm{C}_{1}$ and $\mathrm{C}_{2}$ of a reactant respectively, the order of reaction, 'n' (assuming that the concentrations of all other reactants and T remain constant) with respect to that reactant is given by
(a)$\mathrm{n}=\frac{\log \mathrm{R}_{1}-\log \mathrm{R}_{2}}{\log \mathrm{C}_{1}-\log \mathrm{C}_{2}}$
(b)$\mathrm{n}=\frac{\log \mathrm{C}_{1}-\log \mathrm{C}_{2}}{\log \mathrm{R}_{1}-\log \mathrm{R}_{2}}$
(c)$\mathrm{n}=\frac{\log \mathrm{C}_{1}-\log \mathrm{R}_{1}}{\log \mathrm{C}_{2}-\log \mathrm{R}_{2}}$
(d)$\mathrm{n}=\frac{\log \mathrm{C}_{2}-\log \mathrm{R}_{2}}{\log \mathrm{C}_{1}-\log \mathrm{R}_{1}}$
Answer
SELF-PRACTICE — the source book printed no answer.

Nothing is invented here, so this question has no answer on record.

Explanation
No explanation was printed for this question.

Open in whiteboard · Browse this chapter in the app