ABC26PH0980 · Electrochemistry

Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Exam: NET DEC 2012 · Marks: 2 · Difficulty: Medium

The equilibrium constant for an electrochemical reaction, is
[ left[E_{Fe^{3+}/Fe^{2+}}^{o}=0.75,mathrm{V}, E_{Sn^{4+}/Sn^{2+}}^{o}=0.15,mathrm{V}; dfrac{2.303RT}{F}=0.06,mathrm{V} ight] ]
(a)$10^{10}$
(b)$10^{20}$
(c)$10^{30}$
(d)$10^{40}$
Answer
Answer (as printed): B
Explanation
No explanation was printed for this question.

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