ABC26PH1013 · Electrochemistry

Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Nernst Cells · Exam: NET JUNE 2017 · Marks: 2 · Difficulty: Medium

A solution of $\mathrm{Fe}^{3+}$ is titrated potentiometrically using $\mathrm{Ce}^{3+}$ solution at 25°C. The emf (in V) of the redox system thus formed when, (i) $50 \%$ of $\mathrm{Fe}^{3+}$ and (ii) $80 \%$ of $\mathrm{Fe}^{3+}$ are titrated, would respectively be (Given $\mathrm{E}_{\mathrm{Fe}^{3+} \mathrm{Fe}^{2+}}^{\mathrm{o}}=0.77 \mathrm{V}, \log 2=0.301$ )
(a)0.734 and 0.77
(b)0.77 and 0.385
(c)0.77 and 0.734
(d)0.385 and 0.367
Answer
Answer (as printed): C
Explanation
No explanation was printed for this question.

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