ABC26PH1377 · Statistical Thermodynamics

Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Partition Functions · Exam: NET DEC 2012 · Marks: 2 · Difficulty: Easy

The rotational partition function of $\mathrm{H}_{2}$ is :
(a)$\sum_{\mathrm{J}=0,1,2 }(2 \mathrm{J}+1) \mathrm{e}^{-\beta \mathrm{hcBJ}(\mathrm{J}+1)}$
(b)$\sum_{\mathrm{J}=1,3,5 }(2 \mathrm{J}+1) \mathrm{e}^{-\beta \mathrm{hcBJ}(\mathrm{J}+1)}$
(c)$\sum_{\mathrm{J}=0,2,4 }(2 \mathrm{J}+1) \mathrm{e}^{-\beta h \mathrm{cBJ}(\mathrm{J}+1)}$
(d)$\frac{1}{4}\left[\sum_{\mathrm{J}=0,2,4 }(2 \mathrm{J}+1) \mathrm{e}^{-\beta \mathrm{hcBJ}(\mathrm{J}+1)}+3 \sum_{\mathrm{J}=1,3,5 }(2 \mathrm{J}+1) \mathrm{e}^{-\beta \mathrm{hcBJ}(\mathrm{J}+1)}\right]$
Answer
Answer (as printed): D
Explanation
No explanation was printed for this question.

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