Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Thermodynamics – General · Exam: NET JUNE 2017 · Marks: 2 · Difficulty: Medium
The first excited state $\left({ }^{2} \mathrm{P}_{1 / 2}\right)$ of fluorine lies at an energy of $400 \mathrm{cm}^{-1}$ above the ground state $\left({ }^{2} \mathrm{P}_{3 / 2}\right)$. The fraction of Fluorine atoms in the first excited state at $\mathrm{k}_{\mathrm{B}} \mathrm{T}=420 \mathrm{cm}^{-1}$ is close to