ABC26PH1415 · Surface Chemistry

Subject: Physical Chemistry · Chapter: Surface Chemistry · Topic: Adsorption Isotherms · Exam: NET DEC 2011 · Marks: 2 · Difficulty: Medium

The Langmuir adsorption isotherm is given by $\frac{\mathrm{kp}}{1+\mathrm{kp}}$, where P is the pressure of the adsorabate gas. The Langmuir adsorption isotherm for a diatomic gas $\mathrm{A}_{2}$ undergoing dissociative adsorption is:

(c)$\theta=(\mathrm{Kp})^{2} /\left(1+(\mathrm{Kp})^{2}\right)$

(d)$\theta=(\mathrm{Kp})^{1 / 2}(1+(\mathrm{Kp}))^{1 / 2}$

(a)$\theta=\mathrm{Kp}/(1+\mathrm{Kp})$

(b)$\theta=2\mathrm{Kp}/(1+2\mathrm{Kp})$

Answer

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Explanation

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