ABC26PH1516 · Thermodynamics
Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Laws State Functions · Exam: NET DEC 2019 · Marks: 2 · Difficulty: Medium
Consider the entropy changes in a system undergoing transformation, as depicted in the diagram, below 
The correct statement among the following is (1) $\Delta \mathrm{S}_{1}=\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S} \neq \Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ (2) $\Delta \mathrm{S}_{1}>\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S} \neq \Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ (3) $\Delta \mathrm{S}_{1}=\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S}=\Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ (4) $\Delta \mathrm{S}_{1}>\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S}=\Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ Options
The correct statement among the following is (1) $\Delta \mathrm{S}_{1}=\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S} \neq \Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ (2) $\Delta \mathrm{S}_{1}>\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S} \neq \Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ (3) $\Delta \mathrm{S}_{1}=\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S}=\Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ (4) $\Delta \mathrm{S}_{1}>\Delta \mathrm{S}_{2}$ and $\Delta \mathrm{S}=\Delta \mathrm{S}_{1}+\Delta \mathrm{S}_{2}$ Options(a)1
(b)2
(c)3
(d)4
Answer
Answer (as printed): D
Explanation
No explanation was printed for this question.