Catalytic Cycles: Hydroformylation and the Wacker Process
Industrial catalysis assembled from four elementary steps that repeat in different orders. Learn the steps and any cycle becomes readable.
BSc & MSc · Inorganic Chemistry · Concept
The elementary steps
| Step | What changes | Oxidation state | Electron count |
|---|---|---|---|
| Oxidative addition | A bond adds across the metal | Increases by 2 | Increases by 2 |
| Reductive elimination | Two ligands couple and leave | Decreases by 2 | Decreases by 2 |
| Migratory insertion | A ligand migrates onto an adjacent one | Unchanged | Decreases by 2 |
| Ligand substitution | One ligand replaces another | Unchanged | Unchanged |
A complete cycle must return to the starting complex, and the oxidation states must balance around the loop. Checking that is a good way to verify a proposed mechanism.
Hydroformylation
An alkene, carbon monoxide and hydrogen combine to give an aldehyde with one more carbon. It is one of the largest-volume homogeneous catalytic processes in industry.
- The alkene coordinates to the metal centre.
- A hydride already on the metal migrates onto the alkene, giving a metal alkyl.
- Carbon monoxide coordinates.
- The alkyl migrates onto the carbonyl, giving a metal acyl.
- Hydrogen adds oxidatively.
- Reductive elimination releases the aldehyde and regenerates the catalyst.
The regiochemistry question
Step two can place the metal on either alkene carbon, giving a linear or a branched product. The linear aldehyde is usually wanted, and selectivity for it is improved by using bulky phosphine ligands, which sterically disfavour the branched arrangement.
Explaining how ligand bulk controls product ratio is the standard question, and it illustrates the general principle that ligand design is how selectivity is engineered in homogeneous catalysis.
The Wacker process
An alkene is oxidised to a carbonyl compound — ethene to acetaldehyde in the classic case — using a palladium catalyst with a copper co-catalyst and oxygen.
- The alkene coordinates to palladium(II).
- Water attacks the coordinated alkene, which is now electrophilic.
- Rearrangement and elimination give the carbonyl compound and palladium(0).
- Copper(II) reoxidises the palladium(0) to palladium(II).
- Oxygen reoxidises the copper(I) back to copper(II).
Note also that coordination to palladium reverses the alkene's usual reactivity: normally nucleophilic, a coordinated alkene becomes electrophilic and is attacked by water. That umpolung is worth stating.
Why homogeneous catalysis is studied
- Selectivity can be tuned by changing ligands, which heterogeneous catalysts do not permit so directly.
- Mechanisms are knowable, because the species are in solution and can be studied spectroscopically.
- Milder conditions are often possible.
The offsetting disadvantage is separating catalyst from product, which is trivial for a heterogeneous catalyst and often difficult for a homogeneous one. Stating both sides is expected in a comparison question.
Frequently asked questions
Why does migratory insertion not change oxidation state?
Because no ligand is added or removed and nothing is oxidised or reduced — two ligands already present simply combine. The electron count falls because two ligands become one.
What decides linear versus branched hydroformylation product?
Which carbon of the alkene the hydride migrates to. Bulky phosphine ligands favour the arrangement leading to the linear product.
Why is copper needed in the Wacker process?
To reoxidise palladium(0) back to palladium(II) so the cycle continues. Oxygen then reoxidises the copper, making atmospheric oxygen the ultimate oxidant.
How do I check a proposed catalytic cycle?
Track oxidation state and electron count at every step, and confirm that the cycle returns to the starting complex with both restored. A cycle that does not close is wrong.
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