pH / pOH Calculator

Enter any one of [H⁺], pH, [OH⁻] or pOH and get the other three, using pH + pOH = 14 at 25 °C.

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What it asks for

The formula

pH = −log₁₀[H⁺]    pOH = −log₁₀[OH⁻]

Kw = [H⁺][OH⁻] = 1.0 × 10⁻¹⁴ at 25 °C

Taking −log of the third line:   pH + pOH = 14 (at 25 °C)

Going backwards:   [H⁺] = 10−pH   and   [OH⁻] = 10−pOH

From the article pH and pOH Formulas — The Complete Relationship Explained.

Worked examples

Find pH, pOH and [OH⁻] for a solution with [H⁺] = 1.0 × 10⁻³ M.

pH = −log(1.0 × 10⁻³) = 3.00
pOH = 14 − 3.00 = 11.00
[OH⁻] = 10⁻¹¹ = 1.0 × 10⁻¹¹ M

Check with Kw: (1.0 × 10⁻³)(1.0 × 10⁻¹¹) = 1.0 × 10⁻¹⁴. ✔

Find the pH of 0.00200 M HCl.

HCl is a strong acid, so it ionises completely: [H⁺] = 2.00 × 10⁻³ M
pH = −log(2.00 × 10⁻³) = 3 − log 2.00 = 3 − 0.301 = 2.70

Useful shortcut for exam halls without a calculator: log 2 = 0.301, log 3 = 0.477, log 5 = 0.699, log 7 = 0.845. Almost every printed question uses one of these.

Worked in full in pH and pOH Formulas — The Complete Relationship Explained.

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About this tool

This is one of the tools in the Chemistry Calculator Suite, a free calculator built for IIT-JAM, CSIR-NET, GATE and CUET (Chemical Science) preparation. Nothing is behind a login and no result is stored on a server — the arithmetic runs in your own browser.

The pH / pOH calculator above is the live tool — type your values and press its button; the answer appears in the same box. The link under it opens the full suite with this tool already selected, next to the others.

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