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Class 12 Polymers — Types, Preparation and Degree of Polymerisation

By Aniket Bhardwaj · 19 September 2026 · CBSE/ICSE Concept

Polymers is a short chapter that rewards organised memory more than clever reasoning, and that is exactly why it is worth doing properly: the marks are reliable. Almost every question reduces to one of four things — name the monomer, name the type, state the preparation conditions, or calculate a degree of polymerisation. This guide covers all four, with the arithmetic worked out in full.

The vocabulary, stated precisely

A polymer is a large molecule built by joining many small repeating units. Each small unit is a monomer. The number of repeating units in one polymer chain is the degree of polymerisation, n.
n = molar mass of the polymer ÷ molar mass of the repeating unit

Note the wording: repeating unit, not monomer. For an addition polymer the two are the same thing. For a condensation polymer they are not, because a small molecule is lost when the monomers join — and forgetting that is the single most common numerical error in this chapter.

Classification 1 — by source

TypeMeaningExamples
NaturalOccur in natureCellulose, starch, natural rubber, proteins
Semi-syntheticA natural polymer chemically modifiedCellulose acetate (rayon), cellulose nitrate
SyntheticMade entirely in the laboratory or plantPolythene, nylon, Teflon, PVC, buna-S

Classification 2 — by structure

StructureChainsConsequenceExample
LinearLong straight chains that pack closelyHigh density, high tensile strength, higher melting pointHigh density polythene (HDPE), PVC
BranchedChains with side branches that stop close packingLower density, more flexible, lower melting pointLow density polythene (LDPE)
Cross-linkedChains joined to each other by covalent linksHard, rigid, brittle; cannot be remouldedBakelite, melamine, vulcanised rubber

Classification 3 — by mode of polymerisation

This is the classification questions ask about most.

Addition (chain growth)Condensation (step growth)
Monomer requirementMust contain a double or triple bondMust contain two functional groups
Small molecule lost?No — the polymer has the same empirical formula as the monomerYes — usually H₂O, sometimes HCl, CH₃OH or NH₃
Growth patternChains grow rapidly to full length; monomer is consumed steadilyMonomers form dimers, trimers and so on; long chains appear only late
ExamplesPolythene, PVC, polypropene, Teflon, polyacrylonitrileNylon 6,6, nylon 6, terylene, bakelite, melamine–formaldehyde

Classification 4 — by molecular forces

ClassForce between chainsBehaviourExample
ElastomersWeakest — chains held by a few cross-links onlyStretch a long way and snap backBuna-S, buna-N, neoprene, natural rubber
FibresStrong — hydrogen bonding between chainsHigh tensile strength, thread-like, high melting pointNylon 6,6, terylene
ThermoplasticsIntermediate — no cross-linksSoften on heating, harden on cooling, can be remoulded repeatedlyPolythene, polystyrene, PVC
ThermosettingHeavily cross-linked into a three-dimensional networkSet permanently on moulding; cannot be softened and reusedBakelite, melamine–formaldehyde

Addition polymers and their conditions

Polythene is the standard example, and the two grades are a favourite comparison question.

The free radical mechanism has three stages worth being able to name: initiation (the peroxide breaks homolytically to give radicals), propagation (a radical adds across the C=C of a monomer, regenerating a radical at the new chain end, over and over), and termination (two radicals combine and growth stops).

PolymerMonomerNotes / use
PolytheneEthene, CH₂=CH₂LDPE and HDPE as above
PolypropenePropene, CH₂=CH–CH₃Ropes, pipes, moulded articles
Polyvinyl chloride (PVC)Vinyl chloride, CH₂=CH–ClPipes, raincoats, cable insulation
TeflonTetrafluoroethene, CF₂=CF₂Made with a persulphate or free radical catalyst under pressure; chemically inert, non-stick
Polyacrylonitrile (acrilan)Acrylonitrile, CH₂=CH–CNSubstitute for wool
PolystyreneStyrene, C₆H₅–CH=CH₂Packaging, insulation

Condensation polymers and their monomer pairs

PolymerMonomersConditions (as given in NCERT)Small molecule lost
Nylon 6,6Hexamethylenediamine + adipic acidHeated under high temperature and pressure (about 553 K)Water
Nylon 6Caprolactam (one monomer only)Heated with water at about 533–543 KNone — ring opening, then condensation
Terylene (dacron)Ethylene glycol + terephthalic acidAbout 420–460 K with a zinc acetate–antimony trioxide catalystWater
BakelitePhenol + formaldehydeAcid or base catalyst; the linear novolac is then cross-linked on heatingWater
Melamine–formaldehydeMelamine + formaldehydeCondensation; used for unbreakable crockeryWater

Nylon 6 is worth a second look, because it is the one condensation polymer made from a single monomer. The name refers to the six carbon atoms in caprolactam, not to two different monomers — which is exactly the distinction the "6,6" in nylon 6,6 is making.

Copolymers and rubber

A copolymer is made from more than one kind of monomer. Two are named in the syllabus:

Natural rubber is cis-1,4-polyisoprene. The cis geometry stops the chains packing neatly, which is what makes it elastic. (The trans isomer, gutta-percha, is hard and non-elastic — same monomer, different geometry, opposite properties.) Raw rubber is sticky when hot and brittle when cold, so it is vulcanised: heated with sulphur at about 373–415 K, which introduces sulphur cross-links between the chains and makes the rubber harder, stronger and far more useful.

Biodegradable polymers

Two are named in the syllabus. PHBV is a copolymer of 3-hydroxybutanoic acid and 3-hydroxypentanoic acid, used in packaging and in controlled drug release. Nylon-2-nylon-6 is an alternating polyamide of glycine and aminocaproic acid. Both are broken down by micro-organisms, unlike the ordinary plastics above.

Worked example 1 — degree of polymerisation of polythene

A sample of polythene has an average molar mass of 42,000 g/mol. Find its degree of polymerisation.

Step 1 — molar mass of the repeating unit. For an addition polymer this is the monomer itself, ethene C₂H₄:
C: 2 × 12.011 = 24.022
H: 4 × 1.008 = 4.032
M(C₂H₄) = 24.022 + 4.032 = 28.054 g/mol

Step 2 — divide:
n = 42,000 ÷ 28.054

28.054 × 1000 = 28,054
28.054 × 400 = 11,221.6 → running total 39,275.6
28.054 × 90 = 2,524.86 → running total 41,800.46
28.054 × 7 = 196.378 → running total 41,996.84
Remainder: 42,000 − 41,996.84 = 3.16, and 3.16 ÷ 28.054 ≈ 0.11

n ≈ 1497, i.e. about 1.50 × 10³ repeating units per chain.

Check: 1497 × 28.054 = 41,996.8 g/mol, which rounds to 42,000. ✓

Worked example 2 — working backwards for PVC

A PVC chain contains 800 repeating units. What is its molar mass?

Repeating unit = vinyl chloride, C₂H₃Cl:
C: 2 × 12.011 = 24.022
H: 3 × 1.008 = 3.024
Cl: 1 × 35.45 = 35.450
M = 24.022 + 3.024 = 27.046; 27.046 + 35.450 = 62.496 g/mol

Molar mass of the chain = 800 × 62.496 = 49,996.8 ≈ 5.00 × 10⁴ g/mol

Worked example 3 — a condensation polymer, where the water matters

Find the molar mass of one repeating unit of nylon 6,6.

Hexamethylenediamine, H₂N(CH₂)₆NH₂ = C₆H₁₆N₂:
C: 6 × 12.011 = 72.066; H: 16 × 1.008 = 16.128; N: 2 × 14.007 = 28.014
M = 72.066 + 16.128 = 88.194; + 28.014 = 116.208 g/mol

Adipic acid, HOOC(CH₂)₄COOH = C₆H₁₀O₄:
C: 6 × 12.011 = 72.066; H: 10 × 1.008 = 10.080; O: 4 × 15.999 = 63.996
M = 72.066 + 10.080 = 82.146; + 63.996 = 146.142 g/mol

Route 1 — subtract the water lost. Joining the two monomers at both ends releases two molecules of water:
116.208 + 146.142 = 262.350
262.350 − (2 × 18.015) = 262.350 − 36.030 = 226.320 g/mol

Route 2 — build the repeating unit's formula. It is C₁₂H₂₂N₂O₂:
C: 12 × 12.011 = 144.132; H: 22 × 1.008 = 22.176; N: 2 × 14.007 = 28.014; O: 2 × 15.999 = 31.998
144.132 + 22.176 = 166.308; + 28.014 = 194.322; + 31.998 = 226.320 g/mol

Both routes agree. If you had forgotten the two water molecules you would have written 262.35 instead of 226.32 — an error of about 16%, which changes every answer that depends on it.

Mistakes that lose marks

  • Calling nylon an addition polymer. Nylon 6,6 is a condensation polymer — two functional groups, water lost.
  • Assuming condensation always releases water. Water is the usual small molecule, but HCl, ammonia or an alcohol can be released instead, depending on the monomers.
  • Using the monomer mass for a condensation polymer's repeating unit. Subtract the small molecule lost, as in worked example 3.
  • Mixing up thermoplastic and thermosetting. Thermoplastics soften on heating and can be remoulded; thermosetting polymers are cross-linked and set permanently.
  • Swapping the LDPE and HDPE conditions. LDPE is the high-pressure, free radical, branched one; HDPE is the Ziegler–Natta, low-pressure, linear one.
  • Thinking the "S" in buna-S means sulphur. It means styrene. Sulphur belongs to vulcanisation, which is a different process entirely.
  • Writing natural rubber as trans-polyisoprene. It is the cis isomer; the trans form is gutta-percha and is not elastic.

Where polymers is examined

ExamTypical question
CBSE Class 12Name the monomers of a given polymer; classify by mode of polymerisation and by molecular force; distinguish LDPE and HDPE; explain vulcanisation
ISC Class 12Preparation and uses of nylon, terylene and bakelite; addition vs condensation with examples
NEETDirect monomer-to-polymer matching questions
IIT-JAM / GATEDegree of polymerisation, number-average versus weight-average molar mass, mechanisms

Check the current syllabus on your board's official website before deciding how much time to give this chapter, as its coverage is revised from time to time.

Do the degree-of-polymerisation arithmetic without slips. Enter the monomer formula — C2H4, C2H3Cl, C6H16N2 or C6H10O4 — into the Molar Mass & Composition calculator to get the repeating unit mass, then divide the polymer's molar mass by it. Remember to subtract the small molecule lost for a condensation polymer.

Open the Molar Mass & Composition Calculator →

Working through the Class 12 chemistry syllabus before boards? ABC Chemistry runs Class 11–12 chemistry coaching at its Gurugram centre and online classes across India — details at abcchemistry.in.