ABC26GN0439 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:

Find the least number which when divided by 6, 7, 8, 9 and 12 leaves the same remainder 1 in each case.

Answer

Answer (as printed):

Explanation

Required number = (L.C.M. of 6, 7, 8, 9, 12) + 1. L.C.M. = 3 × 2 × 2 × 7 × 2 × 3 = 504. Hence, required number = (504 + 1) = 505.

Explanation as extracted from the printed page; notation may be imperfect.