ABC26GN0466 · H.C.F. and L.C.M. of Numbers
Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:
The L.C.M. of $2^{3} \times 3^{2} \times 5 \times 11,2^{4} \times 3^{4} \times 5^{2} \times 7$ and $2^{5} \times 3^{3} \times 5^{3} \times 7^{2} \times 11$ is
(a)$2^{3} \times 3^{2} \times 5$
(b)$2^{5} \times 3^{4} \times 5^{3}$
(c)$2^{3} \times 3^{2} \times 5 \times 7 \times 11$
(d)$2^{5} \times 3^{4} \times 5^{3} \times 7^{2} \times 11$
Answer
Explanation
L.C.M. = Product of highest powers of prime factors = $2^{5} \times 3^{4} \times 5^{3} \times 7^{2} \times 11$.
Explanation as extracted from the printed page; notation may be imperfect.
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