ABC26GN0528 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: 2010 · Marks: · Difficulty:

If $r$ is the remainder when each of 7654, 8506 and 9997 is divided by the greatest number $d(d>1)$, then $d-r$ is equal to

(a)14

(b)18

(c)24

(d)28

Answer

Answer (as printed): A

Explanation

$d$ = H.C.F. of (8506 − 7654), (9997 − 8506) and (9997 − 7654) = H.C.F. of 852, 1491 and 2343 = 213. Clearly, $r = 199$. ∴ $d − r = 213 − 199 = 14$.

Explanation as extracted from the printed page; notation may be imperfect.