ABC26GN0527 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

(a)4

(b)7

(c)9

(d)13

Answer

Answer (as printed): A

Explanation

Required number $$\begin{aligned} & =\text { H.C.F. of }(91-43),(183-91) \text { and }(183-43) \\ & =\text { H.C.F. of } 48,92 \text { and } 140=4 . \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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