ABC26GN0720 · Decimal Fractions
Subject: General Aptitude · Chapter: Decimal Fractions · Exam: · Marks: · Difficulty:
The simplification of $3 . \overline{36}-2 . \overline{05}+1 . \overline{33}$ equals
(a)2.60
(b)2.64
(c)2.61
(d)$2 . \overline{64}$
Answer
Explanation
$$\begin{aligned} 3 . \overline{36}-2 . \overline{05}+1 . \overline{33} & =[(3+0 . \overline{36})+(1+0 . \overline{33})]-(2+0 . \overline{05}) \\ & =\left[4+\left(\frac{36}{99}+\frac{33}{99}\right)\right]-\left[2+\frac{5}{99}\right] \\ & =2+\left(\frac{36}{99}+\frac{33}{99}-\frac{5}{99}\right)=2+\frac{64}{99}=2 . \overline{64} . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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