ABC26GN0721 · Decimal Fractions

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: 2003 · Marks: · Difficulty:

$(0 . \overline{09} \times 7 . \overline{3})$ is equal to:
(a). $\overline{6}$
(b). $\overline{657}$
(c). $\overline{67}$
(d). $6 \overline{57}$
Answer
Answer (as printed): A
Explanation
$0 . \overline{09} \times 7 . \overline{3}=\frac{9}{99} \times 7 \frac{3}{9}=\frac{1}{11} \times \frac{66}{9}=\frac{2}{3}=0 . \overline{6}$.

Explanation as extracted from the printed page; notation may be imperfect.

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