ABC26GN0722 · Decimal Fractions

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: 2002 · Marks: · Difficulty:

$(0.34 \overline{67}+0.13 \overline{33})$ is equal to
(a)$0.4 \overline{8}$
(b)$0 . \overline{48}$
(c)$0.48 \overline{01}$
(d)0.48
Answer
Answer (as printed): C
Explanation
$$\begin{aligned} 0.34 \overline{67}+0.13 \overline{33} & =\frac{3467-34}{9900}+\frac{1333-13}{9900}=\frac{3433+1320}{9900} \\ & =\frac{4753}{9900}=\frac{4801-48}{9900}=0.48 \overline{01} . \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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