log ₁₀ 26/51+log ₁₀ 119/91-log ₁₀ 13/32-log ₁₀ 64/39 is equal to · ABC26GN2045

$$\begin{aligned} & \log _{10} \frac{26}{51}+\log _{10} \frac{119}{91}-\log _{10} \frac{13}{32}-\log _{10} \frac{64}{39} \\ & =\left(\log _{10} \frac{26}{51}+\log _{10} \frac{119}{91}\right)-\left(\log _{10} \frac{13}{32}+\log _{10} \frac{64}{39}\right) \\ & =\log _{10}\left(\frac{26}{51} \times \frac{119}{91}\right)-\log _{10}\left(\frac{13}{32} \times \frac{64}{39}\right)=\log _{10} \frac{2}{3}-\log _{10} \frac{2}{3}=0 \end{aligned}$$