ABC26GN2046 · Logarithms
Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:
The value of $\left(\frac{1}{3} \log _{10} 125-2 \log _{10} 4+\log _{10} 32\right)$ is
(a)0
(b)$\frac{4}{5}$
(c)1
(d)2
Answer
Explanation
$$\begin{aligned} & \frac{1}{3} \log _{10} 125-2 \log _{10} 4+\log _{10} 32=\log _{10}(125)^{1 / 3}-\log _{10} \\ & (4)^{2}+\log _{10} 32 \\ & =\log _{10} 5-\log _{10} 16+\log _{10} 32=\log _{10}\left(\frac{5 \times 32}{16}\right) \\ & =\log _{10} 10=1 \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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