ABC26GN2294 · Percentage

Subject: General Aptitude · Chapter: Percentage · Exam: 2008 · Marks: · Difficulty:

In an examination it is required to get 40\% of the aggregate marks to pass. A student get 261 marks and is declared failed by 4\% marks. What are the maximum aggregate marks a student can get?
(a)700
(b)730
(c)745
(d)765
(e)None of these
Answer
Answer (as printed): E
Explanation
Let the maximum marks be $x$. Then, $(40-4) \%$ of $x=261 \Rightarrow 36 \%$ of $x=261$ $$\Rightarrow \quad \frac{36}{100} x=261 \Rightarrow x=\left(\frac{261 \times 100}{36}\right)=725 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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