A candidate has to obtain minimum 33\% of the total marks to pass. He got 25\% of the total marks and failed by 40 marks. The maximum marks are
(a)300
(b)400
(c)500
(d)600
Answer
Answer (as printed): C
Explanation
Let the maximum marks be $x$. Then, 33\% of $x-25 \%$ of $x=40$ $$\begin{aligned} & \Rightarrow \quad 8 \% \text { of } x=40 \Rightarrow \frac{8 x}{100}=40 \\ & \Rightarrow \quad x=\left(\frac{40 \times 100}{8}\right)=500 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.