ABC26GN3014 · Ratio and Proportion
Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
If $\left(4 x^{2}-3 y^{2}\right):\left(2 x^{2}+5 y^{2}\right)=12: 19$, then $x: y$ is
(a)2 : 3
(b)1 : 2
(c)3 : 2
(d)2 : 1
Answer
Explanation
$$\begin{aligned} & \frac{4 x^{2}-3 y^{2}}{2 x^{2}+5 y^{2}}=\frac{12}{19} \Rightarrow 19\left(4 x^{2}-3 y^{2}\right)=12\left(2 x^{2}+5 y^{2}\right) \\ & \Rightarrow 76 x^{2}-57 y^{2}=24 x^{2}+60 y^{2} \\ & \Rightarrow 52 x^{2}=117 y^{2} \Rightarrow 4 x^{2}=9 y^{2} \\ & \Rightarrow \frac{x^{2}}{y^{2}}=\frac{9}{4} \Rightarrow\left(\frac{x}{y}\right)^{2}=\left(\frac{3}{2}\right)^{2} \Rightarrow \frac{x}{y}=\frac{3}{2} . \\ & \therefore x: y=3: 2 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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