ABC26GN3016 · Ratio and Proportion
Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
If $x: y=3: 4$ and $a: b=1: 2$, then the value of $\frac{2 x a+y b}{3 y b-4 x a}$ is
(a)$\frac{5}{6}$
(b)$\frac{6}{5}$
(c)$\frac{6}{7}$
(d)$\frac{7}{6}$
Answer
Explanation
$$\begin{aligned} & \frac{x}{y}=\frac{3}{4} \text { and } \frac{a}{b}=\frac{1}{2} \Rightarrow \frac{x a}{y b}=\frac{3}{4} \times \frac{1}{2}=\frac{3}{8} \\ & \Rightarrow \frac{2 x a+y b}{3 y b-4 x a}=\frac{2\left(\frac{x a}{y b}\right)+1}{3-4\left(\frac{x a}{y b}\right)}=\frac{2 \times \frac{3}{8}+1}{3-4 \times \frac{3}{8}}=\frac{7}{4} \times \frac{2}{3}=\frac{7}{6} . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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