Subject: General Aptitude · Chapter: Races and Games of Skill · Exam: · Marks: · Difficulty:
A runs $1 \frac{2}{3}$ times as fast as $B$. If $A$ gives $B$ a start of 80 m, how far must the winning post be so that $A$ and $B$ might reach it at the same time?
(a)200 m
(b)300 m
(c)270 m
(d)160 m
Answer
Answer (as printed): A
Explanation
Ratio of speeds of $A$ and $B=\frac{5}{3}: 1=5: 3$. Thus, in a race of $5 \mathrm{m}, A$ gains 2 m over $B$. 2 m are gained by $B$ in a race of 5 m. 80 m will be gained by $B$ in a race of $\left(\frac{5}{2} \times 80\right) \mathrm{m}=200 \mathrm{m}$. $$\text { ∴ Winning post is } 200 \text { m away from the starting point }$$