In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race A can beat C by · ABC26GN5124

Subject: General Aptitude · Chapter: Races and Games of Skill

In a 100 m race, $A$ can beat $B$ by 25 m and $B$ can beat $C$ by 4 m. In the same race $A$ can beat $C$ by

(a)21 m

(b)26 m

(c)28 m

(d)29 m

Answer

Answer (as printed): C

Explanation

$A: B=100: 75$ and $B: C=100: 96$. $$A: C=\left(\frac{A}{B} \times \frac{B}{C}\right)=\left(\frac{100}{75} \times \frac{100}{96}\right)=\frac{100}{72} .$$ $\therefore A$ beats $C$ by $(100-72) \mathrm{m}=28 \mathrm{m}$.

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