ABC26IN0002 · Acids and Bases

Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acid and Bases – General · Exam: CSIR-NET DEC 2012 · Marks: 2 · Difficulty: Medium

Match each item from the List-I (compound in solvent) with that from the List-II (its behaviour) and select the correct combination using the codes given below.
List-IList-II
A. $\mathrm{CH_3COOH}$ in pyridine(i) strong acid
B. $\mathrm{CH_3COOH}$ in $\mathrm{H_2SO}$(ii) weak acid
C.$\mathrm{HClO_4}$ in $\mathrm{H_2SO_4}$(iii) strong base
D. $\mathrm{SbF_5}$ in HF(iv) weak base
(a)(A-i), (B-ii), (C-iii), (D-iv)
(b)(A-ii), (B-i), (C-in), (D-iv)
(c)(A-iii), (B-iv), (C-ii), (D-i)
(d)(A-iv), (B-ii), (C-iii), (D-i)
Answer
Answer (as printed): C
Explanation
\[ \mathrm{CH_3COOH + C_5H_5N \rightarrow CH_3COO^{-} + C_5H_5NH^{+}} \quad \text{(solvo cation)} \]
\[ \mathrm{CH_3COOH + H_2SO_4 \rightarrow CH_3COOH_2^{+} + HSO_4^{-}} \quad \text{(solvent anion)} \]
\[ \mathrm{HClO_4 + H_2SO_4 \rightarrow ClO_4^{-} + H_3SO_4^{+}} \quad \text{(solvent cation)} \rightarrow \text{[weak acid]} \]
\[ \mathrm{SbF_5 + 2HF \rightarrow [SbF_6] + H_2F^{+}} \rightarrow \text{[strong acid]} \]

Open in whiteboard · Browse this chapter in the app