Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acid and Bases – General · Exam: CSIR-NET DEC 2012 · Marks: 2 · Difficulty: Easy
The compound that will behave as an acid in $\mathrm{H}_{2} \mathrm{SO}_{4}$ is
(a)$\mathrm{CH_3COOH}$
(b)$\mathrm{HNO_3}$
(c)$\mathrm{HClO_4}$
(d)$\mathrm{H}_{2} \mathrm{O}$
Answer
Answer (as printed): C
Explanation
$\mathrm{HClO_4}$ behave as an acid in $\mathrm{H_2SO_4}$, because $\mathrm{HClO_4}$ contain higher dissociation constant than that of $\mathrm{H_2SO_4}$.$\mathrm{HClO_4}$, $pK_a$ value $-9$. $\mathrm{H_2SO_4}$, $pK_a$ value $-3$. $\mathrm{HNO_3}$, $pK_a$ value $-1$. $\mathrm{CH_3COOH}$, $pK_a$ value $4.7$.$pK_a$ value of $\mathrm{HClO_4}$ > $pK_a$ value of $\mathrm{H_2SO_4}$