The reaction of $[(\eta^{5}\text{-}\mathrm{C_5H_5})(\mathrm{Fe(CO)_2}]^{-}$ with $\mathrm{CH_3I}$ gives compound A. The $^{1}\mathrm{H}$ NMR spectrum of A show two singlets in an integrated intensity ratio of 3:5. Compound A upon reaction with $\mathrm{PPh_3}$ give compound B. The $^{1}\mathrm{H}$ NMR spectrum of B shows 3 sets of signals in an integrated intensity ratio of 3:5:15. Compounds A and B respectively, are
(a)and
(b)and
(c)and
(d)and
Answer
Answer (as printed): B
Explanation
$18e^{-}$ (A) $(18e^{-})$ (B) $(18e^{-})$Two signals with three signal with 3:5:15, 3:5 intensity ratio, intensity ratio