The reaction of [(5-C5H5)Fe(CO)2]- with CH3I gives compound A. The 1H NMR spectrum of A shows two singlets in an integrated intensity ratio of 3:5. Compound A upon reaction with PPh3 give compound B. The 1H NMR spectrum of B shows 3 sets of signals in an integrated intensity ratio of 3:5:15. Compounds A and B respectively, are

ABC26IN1472 · Organometallic Compounds

Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Exam: NET JUNE 2018 · Marks: 2 · Difficulty: Hard

The reaction of $[(\eta^{5}\text{-}\mathrm{C_5H_5})\mathrm{Fe(CO)_2}]^{-}$ with $\mathrm{CH_3I}$ gives compound A. The $^{1}\mathrm{H}$ NMR spectrum of A shows two singlets in an integrated intensity ratio of 3:5. Compound A upon reaction with $\mathrm{PPh_3}$ give compound B. The $^{1}\mathrm{H}$ NMR spectrum of B shows 3 sets of signals in an integrated intensity ratio of 3:5:15. Compounds A and B respectively, are

(a)

(b)

and

(c)

(d)

and

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.

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