Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Enzyme Kinetics · Exam: CSIR-NET JUNE 2018 · Marks: 2 · Difficulty: Medium
For an enzyme-substrate reaction,
\[ \begin{array}{c} E+S \stackrel{k_{1}}{\underset{k_{-1}}{\rightleftharpoons}} E S E S \xrightarrow{k_{2}} E+P, \end{array} \]
the slope and intercept of plot between $\frac{1}{r}$ and $\frac{1}{[s]}$ are $10^{-2} \mathrm{s}$ and $10^{2} \mathrm{M}^{-1} \mathrm{s}$, respectively. If $E_{0}=10^{-6} M$ and $\frac{k_{-1}}{k_{2}}=1000$, the value of $k_{1}$ will be close to (in units of $\mathrm{M}^{-1} \mathrm{s}^{-1}$ ) [ $r$ is the rate of reaction and $\mathrm{E}_{\mathrm{o}}$ is initial concentration of enzyme
(a)$1 \times 10^{11}$
(b)$1 \times 10^{4}$
(c)$1 \times 10^{8}$
(d)$1 \times 10^{6}$
Answer
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