ABC26PH0948 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Enzyme Kinetics · Exam: NET JUNE 2018 · Marks: 2 · Difficulty: Medium

For an enzyme-substrate reaction,
\[ \mathrm{E}+\mathrm{S} \underset{\mathrm{k}_{-1}}{\stackrel{\mathrm{k}_{1}}{\rightleftharpoons}} \mathrm{ES} \]
the slope and intercept of plot between $1 / \mathrm{r}$ and $1 /[\mathrm{S}]$ are $10^{-2} \mathrm{s}$ and $10^{2} \mathrm{M}^{-1} \mathrm{s}$, respectively, If $\mathrm{E}_{0}=10^{-6} \mathrm{M}$ and $\frac{\mathrm{k}_{-1}}{\mathrm{k}_{2}}=1000$, the value of $\mathrm{k}_{1}$ will be close to (in units of $\mathrm{M}^{-1} \mathrm{s}^{-1}$ ) [r is the rate of reaction and $\mathrm{E}_{0}$ is initial concentration of enzyme
(a)$1 \times 10^{11}$
(b)$1 \times 10^{4}$
(c)$1 \times 10^{8}$
(d)$1 \times 10^{6}$
Answer
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Explanation
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