Question Bank › Physical Chemistry › Atomic Structure › ABC26PH0277ABC26PH0277 · Atomic Structure Subject: Physical Chemistry · Chapter: Atomic Structure · Topic: Atomic Structure – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium
The quantum state of a particle moving in a circular path in a plane is given by \[ \psi_{\mathrm{m}}(\phi)=(1 / \sqrt{2 \pi}) \mathrm{e}^{\mathrm{im} \phi}, \mathrm{m}=0, \pm 1, \pm 2, \]
When a perturbation $\mathrm{H}_{1}=\mathrm{P} \cos \phi$ is applied ( P is a constant), what will be the first order correction to the energy of the $\mathrm{m}^{\text {th }}$ state (a) 0
(b) $P/(2\pi)$
(c) $P/(4\pi)$
(d) $Pm^{2}/(4\pi^{2})$
Answer Explanation No explanation was printed for this question.
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