Consider a particle of mass $m$ moving in a one-dimensional box under the potential $V=0$ for $0\leq x\leq a$ and $V=\infty$ outside the box. When the particle is in its lowest energy state the average momentum ($\langle p_x\rangle$) of the particle is
(a)$\langle p_x\rangle=0$
(b)$\langle p_x\rangle=\frac{h}{a}$
(c)$\langle p_x\rangle=\frac{h}{2a}$
(d)$\langle p_x\rangle=\frac{h}{2\pi a}$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
A real stationary box wavefunction has ⟨pₓ⟩ = 0 (a).