ABC26PH0923 · Chemical Kinetics
Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Exam: NET JUNE 2015 · Marks: 2 · Difficulty: Medium
In a photochemical reaction, radicals formed according to the equation \[ \begin{array}{l} \mathrm{C}_{4} \mathrm{H}_{10}+\mathrm{hv} \leftrightharpoons 2 \mathrm{C}_{2} \mathrm{H}_{5} \\ \mathrm{C}_{2} \mathrm{H}_{5}+\mathrm{C}_{2} \mathrm{H}_{5} \xrightarrow{\mathrm{k}_{2}} \mathrm{C}_{2} \mathrm{H}_{6}+\mathrm{C}_{2} \mathrm{H}_{4} \end{array} \]
If I is the intensity of light absorbed, the rate of the overall reaction is proportional to- (a)I
(b)$\mathrm{I}^{1 / 2}$
(c)$\mathrm{I}\left[\mathrm{C}_{4} \mathrm{H}_{10}\right]$
(d)$\mathrm{I}^{1 / 2}\left[\mathrm{C}_{4} \mathrm{H}_{10}\right]^{1 / 2}$
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.
Explanation
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