Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Vibrational · Exam: NET JUNE 2011 · Marks: 2 · Difficulty: Medium
The vibrational energy levels, $v^{\prime \prime}=0$ and $v^{\prime}=1$ of a diatomic molecule are separated by $2143 \mathrm{cm}^{-1}$. Its anharmonicity wexe is $14 \mathrm{cm}^{-1}$. The values of $\omega \mathrm{e}$ (in $\mathrm{cm}^{-1}$ ) and first overtone $\left(\mathrm{cm}^{-1}\right)$ of this molecule are respectively.