Use P₁V₁/T₁ = P₂V₂/T₂ for a fixed amount of gas: fill five of the six values, with temperatures in kelvin, and solve for the one you leave blank.
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From the article Combined Gas Law — One Formula for Boyle, Charles and Gay-Lussac.
A gas occupies 250 mL at 25 °C and 1.00 atm. What volume will it occupy at 100 °C and 0.80 atm?
Convert temperatures first: T₁ = 25 + 273 = 298 K, T₂ = 100 + 273 = 373 K.
V₂ = P₁V₁T₂ ÷ (T₁P₂)
Numerator: 1.00 × 250 × 373 = 93 250
Denominator: 298 × 0.80 = 238.4
V₂ = 93 250 ÷ 238.4 = 391 mL
Sanity check: heating expands the gas and lowering the pressure expands it further, so the volume must increase. 391 mL > 250 mL. Correct direction.
Worked in full in Combined Gas Law — One Formula for Boyle, Charles and Gay-Lussac.
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