ABC26GN4454 · Area

Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:

Consider the given figure. ![]( If the areas of the triangles LDC, BMC and AMC are denoted by $x, y$ and $z$ respectively, then
(a)$x=y=z$
(b)$x=2 y=2 z$
(c)$y=2 x=2 z$
(d)$z=2 x=2 y$
Answer
Answer (as printed): B
Explanation
$x=\frac{1}{2} \times C D \times L M ; y=\frac{1}{2} \times C M \times B C=\frac{1}{2} \times\left(\frac{1}{2} C D\right) \times L M$ $=\frac{1}{4} \times C D \times L M=\frac{1}{2} x$; $z=\frac{1}{2} \times C M \times L M=\frac{1}{2} \times\left(\frac{1}{2} C D\right) \times L M=\frac{1}{4} \times C D \times L M=\frac{1}{2} x$. $\therefore \quad x=2 y=2 z$.

Explanation as extracted from the printed page; notation may be imperfect.

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