ABC26GN4455 · Area
Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
If the area of a triangle is $1176 \mathrm{cm}^{2}$ and base : corresponding altitude is 3 : 4, then the altitude of the triangle is
(a)42 cm
(b)52 cm
(c)54 cm
(d)56 cm
Answer
Explanation
Let base $=3 x \mathrm{cm}$ and altitude $=4 x \mathrm{cm}$. Then, $\frac{1}{2} \times 3 x \times 4 x=1176 \Leftrightarrow 12 x^{2}=2352$ $\Leftrightarrow x^{2}=196 \Leftrightarrow x=14 \mathrm{cm}$. ∴ Altitude $=(4 \times 14) \mathrm{cm}=56 \mathrm{cm}$.
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