Out of a square of side 8 cm, a triangle is drawn with base as one side of the square and third vertex at any… · ABC26GN4453
Subject: General Aptitude · Chapter: Area
Out of a square of side 8 cm, a triangle is drawn with base as one side of the square and third vertex at any point on the opposite side of the square. What is the area of the remaining portion of the square if the triangle is taken out?
(a)16 sq. cm
(b)32 sq. cm
(c)64 sq. cm
(d)Cannot be determined
(e)None of these
Answer
Answer (as printed): B
Explanation
Base of the triangle = 8 cm. Height of the triangle = 8 cm. Area of the triangle $=\left(\frac{1}{2} \times 8 \times 8\right) \mathrm{cm}^{2}=32 \mathrm{cm}^{2}$. Area of the square $=(8 \times 8) \mathrm{cm}^{2}=64 \mathrm{cm}^{2}$. ∴ Required area $=(64-32) \mathrm{cm}^{2}=32 \mathrm{cm}^{2}$.