Paper: CSIR-NET December 2011 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Medium
Match list I (compounds) with list II (structures), and select the correct answer using the codes given below.
List-I
List-II
(A) $\mathrm{XeO_4}$
(i) square planar
(B) $\mathrm{BrF_4^{-}}$
(ii) tetrahedral
(C) $\mathrm{SeCl_4}$
(ii) distorted tetrahedral..
(a)(A-ii) (B-iii) (C-i)
(b)(A- iii) (B-i) (C-ii)
(c)(A-ii) (B-i) (C-iii)
(d)(A-i) (B-ii) (C-iii)
Answer
Answer: C ✓ checked by 4AB · confidence high
A-ii, B-i, C-iii. The third List-II entry, distorted tetrahedral, is misprinted as (ii) in the source; the codes call it (iii).
Explanation
XeO₄: Xe(VIII) has 4 bond pairs and no lone pair → tetrahedral (ii). BrF₄⁻: Br has 4 bond pairs and 2 lone pairs (AX₄E₂) → square planar (i). SeCl₄: Se has 4 bond pairs and 1 lone pair (AX₄E) → see-saw, i.e. distorted tetrahedral. This is the third List-II entry: the source misprints it as (ii), but the codes call it (iii). Match: A-ii, B-i, C-iii — option (c).